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In Young's experiment, if the distance between the two slits is doubled then the width of the fringes will be

Asked in GSEB Board March 2016 · Fringe width and fringe position

Answer: (2) Halved

Step-by-step solution

Given: the slit separation is changed from d to 2d, with λ and D the same.

Idea: the fringe width is β=(λ D)/d, inversely proportional to the separation of the slits.

β'=(λ D)/(2d).

β'=β/2.

So the fringes are half as wide: moving the slits apart crowds the pattern, bringing them closer spreads it out.

Why the other options are wrong

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