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If the phase difference between two waves is 6π radian, then the corresponding path difference is

Asked in GSEB Board July 2021 · Intensity and coherent sources

Answer: (4) 3λ

Step-by-step solution

Given: phase difference Δφ=6π rad between two waves.

Idea: a path difference of one whole wavelength puts the waves 2π out of phase, so the two are tied by Δ x=λ/(2π)Δφ.

Δ x=λ/(2π)×6π.

Δ x=3λ.

Three whole wavelengths is an even multiple of λ/2, so the two waves arrive in step and the point is bright.

Why the other options are wrong

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