In a two-slit experiment the screen is placed one metre away. When light of wavelength 500 nm is used the fringe separation is 0.5 mm. The distance between the two slits is mm.

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(3) 1. Given: D = 1 m, λ = 500 nm = 5×10⁻⁷ m, and a fringe separation β = 0.5 mm = 5×10⁻⁴ m. Idea: the separation of neighbouring fringes is the fringe width β = (λ D)/d, so the unknown slit separation comes from rearranging it. d = (λ D)/β = ((5×10⁻⁷)(1))/(5×10⁻⁴). d = 1×10⁻³ m. The two slits are 1 mm apart.

In a two-slit experiment the screen is placed one metre away. When light of wavelength 500 nm is used the fringe separation is 0.5 mm. The distance between the two slits is ________ mm.

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