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Asked in GSEB Board July 2017 · Brewster's law and polarisation by reflection
Given: μ=1.327 for the water, and the reflected sunlight is found to be completely polarised.
Idea: complete polarisation on reflection happens at Brewster's angle, tan iₚ=μ, with iₚ measured from the normal -- and the normal to a still lake points straight up.
iₚ=tan⁻¹1.327=53°.
The incident ray therefore makes 53° with the vertical.
The angle it makes with the horizontal is 90°-53°.
So the Sun is seen 37° above the horizon.
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