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Asked in GSEB Board July 2015 · Brewster's law and polarisation by reflection
Given: light incident at the polarising angle iₚ, the refracted ray deviated by 22° from the incident direction.
Idea: at the polarising angle the reflected and refracted rays are perpendicular to each other, which forces iₚ+r=90°.
The refracted ray is bent towards the normal, so its deviation is iₚ-r=22°.
Adding the two relations: 2iₚ=112°, so iₚ=56°.
Subtracting them: 2r=68°.
r=34°.
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