Practice portal › Electric Charge and Properties › Electric Flux and Gauss's Law
Asked in GSEB Board July 2021 · Units and dimensions
Given: electric flux.
Idea: the unit is the quickest way in. E is measured in V m⁻¹ and an area in m², so a flux is measured in V m.
[V]=M¹L²T⁻³A⁻¹ -- a joule per coulomb, (M¹L²T⁻²)/(T¹A¹).
Multiplying by one metre: [Φ_E]=M¹L²T⁻³A⁻¹×L¹=M¹L³T⁻³A⁻¹.
So the dimension of electric flux is M¹L³T⁻³A⁻¹.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer