Practice portal › Electromagnetic Induction › Mutual Inductance
Asked in GSEB Board March 2020 · Units and dimensions
Given: the mutual inductance M of a pair of coils.
Idea: Φ₂=MI₁ -- the flux linked with the second coil per unit current in the first -- so M=(Φ₂)/(I₁).
[Φ]=M¹L²T⁻²A⁻¹ and [I]=A¹, so [M]=M¹L²T⁻²A⁻².
This is the same set as for self inductance, as it must be: both are measured in henry, and M=k√L₁L₂ with the coupling constant k a pure number.
So mutual inductance has the dimensions M¹L²T⁻²A⁻².
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