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Select the dimensional formula of (B²)/(2μ₀).

Asked in GUJCET 2017 · Dimensional formula of a named quantity

Answer: (4) M¹L⁻¹T⁻²

Step-by-step solution

Given: the combination (B²)/(2μ₀).

Idea: this is the energy stored per unit volume of a magnetic field, so it must come out with the dimensions of energy density -- the same as pressure.

From F=BIℓ, [B]=(M¹L¹T⁻²)/(A¹L¹)=M¹L⁰T⁻²A⁻¹, and [μ₀]=M¹L¹T⁻²A⁻².

([B]²)/([μ₀])=(M²L⁰T⁻⁴A⁻²)/(M¹L¹T⁻²A⁻²)=M¹L⁻¹T⁻².

Check: (energy)/(volume)=(M¹L²T⁻²)/(L³)=M¹L⁻¹T⁻², the same.

So the answer is M¹L⁻¹T⁻²; the 2 is a pure number and carries no dimensions.

Why the other options are wrong

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