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Asked in GSEB Board March 2020 (old course) · Deviation and minimum deviation
Given: an equilateral prism, so A=60°; angle of incidence i=48° 52' and angle of emergence e=50° 53'.
Idea: for a prism the deviation is δ=i+e-A, whatever the path inside.
Add the minutes first: 52'+53'=105', and 105'=1° 45'.
Add the degrees: 48°+50°=98°, so i+e=99° 45'.
δ=99° 45'-60°=39° 45'
Note i and e are not equal here, so the prism is not set at minimum deviation.
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