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When a ray of monochromatic light is made incident on an equilateral prism at an angle of 48° 52', the angle of emergence is 50° 53'. Calculate the value of the angle of deviation.

Asked in GSEB Board March 2020 (old course) · Deviation and minimum deviation

Answer: (1) 39° 45'

Step-by-step solution

Given: an equilateral prism, so A=60°; angle of incidence i=48° 52' and angle of emergence e=50° 53'.

Idea: for a prism the deviation is δ=i+e-A, whatever the path inside.

Add the minutes first: 52'+53'=105', and 105'=1° 45'.

Add the degrees: 48°+50°=98°, so i+e=99° 45'.

δ=99° 45'-60°=39° 45'

Note i and e are not equal here, so the prism is not set at minimum deviation.

Why the other options are wrong

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