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Asked in GSEB Board July 2023 · Deviation and minimum deviation
Given: a thin prism with A=6° and minimum deviation δₘ=3°.
Idea: for a thin prism both angles are small, and the general prism formula collapses to δₘ=(n-1)A.
3°=(n-1)× 6°
n-1=3/6=0.5
n=1.5
The full formula agrees: n=(sin ((A+δₘ)/2))/(sin (A/2))=(sin 4.5°)/(sin 3°)=1.50.
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