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Asked in GUJCET 2021 · Snell's law, slabs and apparent depth
Given: real depth d=16 cm, refractive index of water μ_w=4/3.
Idea: seen from straight above, the bottom of a liquid appears raised; the apparent depth is d/(μ_w).
Dividing by 4/3 is multiplying by 3/4: apparent depth =16×3/4.
So the needle appears to lie 12.0 cm below the water surface.
It has been raised by 4 cm, a quarter of the real depth.
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