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A glass prism having refractive index μ is placed in air. For it the angle of minimum deviation of the prism is the same as the angle of the prism. Then what is the value of the angle of the prism?

Asked in GUJCET 2021 · Deviation and minimum deviation

Answer: (1) 2 cos⁻¹(μ/2)

Step-by-step solution

Given: a prism of refractive index μ in air with δₘ=A.

Idea: at minimum deviation the ray is symmetric and μ=(sin ((A+δₘ)/2))/(sin (A/2)).

Put δₘ=A: μ=(sin A)/(sin (A/2)).

Now sin A=2 sin (A/2)cos (A/2), so the sines cancel and μ=2 cos (A/2).

Hence cos (A/2)=μ/2.

Taking the inverse cosine and doubling, A=2 cos⁻¹(μ/2).

Why the other options are wrong

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