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Complete the following nuclear reaction. ²³⁵₉₂U+¹₀n→ ______ + ⁹⁹₄₁Nb+4 ¹₀n

Asked in GSEB Board July 2022 · Q-value, decay and conservation laws

Answer: (1) ¹³³₅₁Sb

Step-by-step solution

Idea: balance charge and nucleon number separately. Call the missing fragment ^A_ZX.

Charge: 92+0=Z+41+0, so Z=51 — antimony.

Nucleons: 235+1=A+99+4, so A=236-103=133.

The missing fragment is ¹³³₅₁Sb.

The trap here is the pair of half-right options: one balances only the charge, the other only the mass number. Both counts have to come out.

Why the other options are wrong

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