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Asked in GSEB Board August 2020 · Q-value, decay and conservation laws
Idea: nucleon number and charge are conserved. Call the missing fragment ^A_ZX and write one equation for each.
Nucleons: 1+235=236=144+A+3, so A=236-147=89.
Charge: 0+92=56+Z+0, so Z=36.
Z=36 is krypton, so the missing fragment is ⁸⁹₃₆Kr.
This is the textbook fission channel of ²³⁵₉₂U: barium, krypton and three neutrons.
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