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Asked in GUJCET 2024 · Q-value, decay and conservation laws
Idea: charge and nucleon number are both conserved, which gives one equation each.
Charge: 92+0=x+41+0, so x=51 — the fragment is ¹³³₅₁Sb, antimony.
Nucleons: 235+1=133+y+4, so y=236-137=99 — the other fragment is ⁹⁹₄₁Nb.
Hence (x,y)=(51, 99).
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