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A toroid wound with 100 turns per metre of wire carries a current of 3 A. The core of the toroid is made of iron having relative magnetic permeability μᵣ=5000 under the given conditions. The magnetic field inside the iron is ______. (μ₀=4π×10⁻⁷ T m A⁻¹)

Asked in GSEB Board July 2018 · Magnetisation, intensity and susceptibility

Answer: (4) 1.88 T

Step-by-step solution

Given: n=100 turns per metre, I=3 A, μᵣ=5000, μ₀=4π×10⁻⁷ T m A⁻¹.

Idea: inside a toroid the magnetising field is H=nI (Ampere's circuital law), and the iron core multiplies the field by its relative permeability: B=μ₀μᵣ H.

H=nI=100×3=300 A m⁻¹.

μᵣ H=5000×300=1.5×10⁶ A m⁻¹.

B=4π×10⁻⁷×1.5×10⁶=1.88 T - a field the winding alone could never produce, which is what a ferromagnetic core is for.

Why the other options are wrong

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