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Asked in GSEB Board July 2023 · Crossed electric and magnetic fields
Given: a positive charge q at position ⃗r, moving with velocity ⃗v antiparallel to ⃗B(⃗r), with an electric field ⃗E(⃗r) present as well.
Idea: both fields act through the Lorentz force ⃗F=q⃗E+q(⃗v×⃗B).
Magnetic term: the angle between ⃗v and ⃗B is 180°, so |⃗v×⃗B|=vB sin 180°=0 — the magnetic field does nothing to this charge.
Electric term: on a positive charge the force is q⃗E(⃗r), along the field.
So the total force is q⃗E(⃗r), whatever the time t.
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