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Asked in GSEB Board July 2017 · Crossed electric and magnetic fields
Given: ⃗E and ⃗B both point downward, and an electron (charge -e) moves downward.
Idea: the Lorentz force is ⃗F=q[⃗E+(⃗v×⃗B)], here with q=-e.
Magnetic part: ⃗v is parallel to ⃗B, so ⃗v×⃗B=0 and there is no magnetic force — hence no deflection.
Electric part: ⃗F=-e⃗E points upward, opposite to the velocity.
A force opposite to the motion does negative work, so the electron slows down: it loses velocity.
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