Practice portal › Moving Charges and Magnetism › Moving Coil Galvanometer and its Conversion
Asked in GSEB Board March 2023 · Conversion to ammeter and voltmeter
Given: G=10 Ω, I_g=3 mA=3×10⁻³ A, and a full-scale reading of I=10 A.
Idea: the shunt sits in parallel with the coil and carries everything the coil does not, namely I-I_g. Being in parallel, the two have the same potential difference across them.
I_gG=(I-I_g)S
S=(3×10⁻³×10)/(10-3×10⁻³)=(0.03)/(9.997)
S=3.0×10⁻³ Ω, that is 3 mΩ.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer