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Asked in GSEB Board March 2019 · Crossed electric and magnetic fields
Given: ⃗E and ⃗B both point upward; an electron travels downward.
Idea: use the Lorentz force ⃗F=q⃗E+q(⃗v×⃗B) with q=-e, and take the two parts separately.
Magnetic part: ⃗v is antiparallel to ⃗B, so ⃗v×⃗B=0 — no magnetic force, and therefore no bending.
Electric part: on a negative charge the force is opposite to ⃗E, so it points downward.
That force lies along the electron's own motion, so it does positive work and the electron gains speed.
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