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Asked in GUJCET 2022 · Solenoid, toroid and field energy
Given: L=0.25 m, N=500 turns, I=2.5 A, μ₀=4π×10⁻⁷ SI. The radius 1 cm is not needed: inside a long solenoid the field does not depend on it.
Idea: B=μ₀ n I, where n is the number of turns per metre.
n=N/L=(500)/(0.25)=2000 m⁻¹.
B=4π×10⁻⁷×2000×2.5=4π×10⁻⁷×5000.
B=2π×10⁻³=6.28×10⁻³ T.
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