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Asked in GUJCET 2019 · Solenoid, toroid and field energy
Given: 50 turns per cm, so the turn density is n=50×100=5000 turns per metre; I=2.5 A.
Idea: well inside a long solenoid the field is uniform and along the axis, B=μ₀nI.
B=4π×10⁻⁷×5000×2.5.
=4π×1.25×10⁻³=5π×10⁻³ T, about 1.57×10⁻² T.
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