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Asked in GUJCET 2014 · Rotating charges and multiple loops
Given: N=25 turns in each ring; r₁=50 cm=0.5 m with I₁=0.1 A, r₂=200 cm=2 m with I₂=0.2 A, the currents opposite.
Idea: each ring contributes B=(μ₀NI)/(2r) at the common centre; opposite currents put the two contributions in opposite directions, so they subtract.
B₁=(μ₀×25×0.1)/(2×0.5)=2.5μ₀
B₂=(μ₀×25×0.2)/(2×2)=1.25μ₀
Net B=B₁-B₂=1.25μ₀=5/4μ₀, in the sense of the inner ring.
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