Practice portal › Moving Charges and Magnetism › Field of a Circular Loop
Asked in GUJCET 2007 · Rotating charges and multiple loops
Given: two identical coils, same N and same I, sharing a centre, with their planes perpendicular.
Idea: each coil's field at the centre points along that coil's own axis, so the two fields are at right angles to each other.
Each coil alone gives the same magnitude B=(μ₀ N I)/(2R).
Perpendicular vectors add in quadrature: Bₙₑₜ=√B²+B²=√2 B.
So Bₙₑₜ : B=√2 : 1.
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