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Asked in GSEB Board March 2019 · Relation between field and potential
Given: ⃗E=E₀̂j everywhere, and V=0 at y=0.
Idea: potential and field are linked by V_B-V_A=-∫_A^B⃗E·d⃗l.
Go from y=0 to y along the y-axis: d⃗l=dy ̂j, so ⃗E·d⃗l=E₀ dy.
V(y)-0=-∫₀^yE₀ dy=-E₀y.
So V=-yE₀: the potential drops steadily as you move along the field.
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