The distance between the two extreme points of the wings of an aeroplane is 50 m. It is flying horizontally at a speed of 360 km h⁻¹. If the vertical component of Earth's magnetic field at that place is 2×10⁻⁴ Wb m⁻², the induced emf between these two end points is V.

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(1) 1.0. Given: wing span ℓ = 50 m; speed v = 360 km h⁻¹; vertical field B_V = 2×10⁻⁴ Wb m⁻². Idea: the wings act as a rod moving horizontally, so only the vertical component of Earth's field is cut: ε = B_V ℓ v. Convert the speed: v = (360 × 1000)/(3600) = 100 m s⁻¹. ε = 2×10⁻⁴ × 50 × 100 = 1.0 V. So the emf between the wing tips is 1.0 V.

The distance between the two extreme points of the wings of an aeroplane is 50 m. It is flying horizontally at a speed of 360 km h⁻¹. If the vertical component of Earth's magnetic field at that place is 2×10⁻⁴ Wb m⁻², the induced emf between these two end points is ______ V.

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