Practice portal › Electromagnetic Induction › Self-Inductance
Asked in GUJCET 2018 · Coil geometry, cores and combinations
Given: L in parallel with L, and that pair in series with 5 mH; total 15 mH.
Idea: with no mutual inductance, inductors combine like resistors.
Two equal inductors in parallel: Lₚ=(L· L)/(L+L)=L/2.
In series with 5 mH: L/2+5=15, so L/2=10 mH.
So L=20 mH.
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