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Asked in GUJCET 2009 · Flux change and induced EMF
Given: Φ=5t²+2t+3 in webers.
Idea (Faraday's law): the induced emf is the rate of change of flux, ε=-(dΦ)/(dt).
(dΦ)/(dt)=10t+2; the constant 3 does not change, so it adds nothing.
At t=1 s: (dΦ)/(dt)=10+2=12 Wb s⁻¹.
So the magnitude of the induced emf is 12 V.
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