Practice portal › Electromagnetic Induction › Faraday's Law
Asked in GUJCET 2014 · Flux change and induced EMF
Given: N = 500; A = 0.15 m²; B changes from 0.2 T to 1.0 T in Δ t = 0.4 s, perpendicular to the area.
Idea: Faraday's law, |ε| = N (ΔΦ)/(Δ t) = NA (Δ B)/(Δ t).
Δ B = 1.0 - 0.2 = 0.8 T, so (Δ B)/(Δ t) = (0.8)/(0.4) = 2 T s⁻¹.
|ε| = 500 × 0.15 × 2 = 150 V.
So the induced emf is 150.0 volt.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer