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A conducting coil having 500 turns has a cross-sectional area of 0.15 m². A magnetic field of 0.2 T, perpendicular to this area, changes to 1.0 T in 0.4 s. The induced emf produced in the coil will be ______ volt.

Asked in GUJCET 2014 · Flux change and induced EMF

Answer: (4) 150.0

Step-by-step solution

Given: N = 500; A = 0.15 m²; B changes from 0.2 T to 1.0 T in Δ t = 0.4 s, perpendicular to the area.

Idea: Faraday's law, |ε| = N (ΔΦ)/(Δ t) = NA (Δ B)/(Δ t).

Δ B = 1.0 - 0.2 = 0.8 T, so (Δ B)/(Δ t) = (0.8)/(0.4) = 2 T s⁻¹.

|ε| = 500 × 0.15 × 2 = 150 V.

So the induced emf is 150.0 volt.

Why the other options are wrong

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