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Asked in RS Academy GUJCET booklet · Dipole moment and dipole field
Given: p = 3.4×10⁻³⁰ C m, separation d = 1.0 A = 1.0×10⁻¹⁰ m.
Idea: dipole moment p = qd, so q = p/d.
q = (3.4×10⁻³⁰)/(1.0×10⁻¹⁰) = 3.4×10⁻²⁰ C
This is only about a fifth of e: in HCl the bonding electrons are shared unequally, not transferred whole.
So each charge has magnitude 3.4×10⁻²⁰ C.
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