When a 10 μC charge is enclosed by a closed surface, the flux passing through the surface is φ. Now another -5 μC charge is placed inside the same closed surface. The flux passing through the surface is then _.

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(2) φ/2. Given: q₁=10 μC inside gives flux φ; a second charge q₂=-5 μC is added inside. Idea: Gauss's law. The flux through a closed surface depends only on the net charge enclosed: φ=(qᵢₙ)/(ε₀). Before: φ=(10 μC)/(ε₀) After: qᵢₙ=10+(-5)=5 μC, so φ'=(5 μC)/(ε₀) (φ')/φ=5/(10)=1/2 So the flux becomes φ/2.

When a 10 μC charge is enclosed by a closed surface, the flux passing through the surface is φ. Now another -5 μC charge is placed inside the same closed surface. The flux passing through the surface is then _______.

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Why the other options are wrong