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Asked in GSEB Board March 2020 (old course) · Electric flux through a surface
Given: ⃗E=100 N C⁻¹ along X; a square of side 0.10 m lying in the XY plane.
Idea: the flux through a flat surface is φ=⃗E·⃗A=EA cos θ, where θ is the angle between the field and the normal to the surface.
A square lying in the XY plane has its normal along the Z-axis.
The field is along X, perpendicular to Z, so θ=90°.
φ=(100)(0.10)² cos 90°=0
The field lines run along the square, never through it, so the flux is zero.
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