In the absence of gravity, a charge q and mass 2m is placed stationary in a uniform electric field of intensity E. When the charge is released, its speed after n seconds is .

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(3) (qEn)/(2m). Given: charge q, mass 2m, a uniform field E, released from rest, and no gravity to complicate things. Idea: the only force acting is the electric force qE. It is constant, so the motion is uniformly accelerated from rest and the equations of motion apply directly. a = F/(mass) = (qE)/(2m) v = u + at = 0 + (qE)/(2m)× n So the speed after n seconds is (qEn)/(2m) - it grows in proportion to the time, since the acceleration never changes.

In the absence of gravity, a charge q and mass 2m is placed stationary in a uniform electric field of intensity E. When the charge is released, its speed after n seconds is ________.

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