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Asked in GUJCET 2025 · Shell and uniform solid sphere
Given: a point charge 2q produces E=(k(2q))/(r²)=(2kq)/(r²) at distance r.
Idea: outside a uniformly charged thin shell the field is the same as if the whole charge sat at the centre.
The condition r R puts the field point at r/2 well outside the shell, so the shell acts as a point charge q:
E'=(kq)/((r/2)²)=(4kq)/(r²)
Comparing the two, (E')/E=(4kq/r²)/(2kq/r²)=2.
Halving the charge halves the field, but halving the distance quadruples it, so E'=2E.
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