Practice portal › Electric Charge and Properties › Electric Field of Point Charges
Asked in GUJCET 2019 · Field of discrete charges
Given: q = 1 μC = 10⁻⁶ C on five corners of a regular hexagon of side 1 m; each corner is r = 1 m from the centre, since a regular hexagon's side equals its centre-to-corner distance.
Idea: charges at opposite corners produce equal and opposite fields at the centre.
Of the five filled corners, two opposite pairs cancel; the charge opposite the empty corner is left unpaired.
E = (Kq)/(r²) = (K×10⁻⁶)/(1²) = 10⁻⁶K
The field points from that unpaired charge towards the empty corner.
So E = 10⁻⁶K N C⁻¹.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer