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Asked in GUJCET 2015 · Properties of charge
Given: n=10¹⁹ electrons removed; e=1.6×10⁻¹⁹ C.
Idea: charge is quantised, q=ne. Removing electrons leaves an excess of protons, so the plate becomes positive.
q=ne=10¹⁹×1.6×10⁻¹⁹
q=+1.6 C
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