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Three identical charges q₁, q₂ and q₃ are placed, in that order, on three consecutive vertices of a square. If the force acting between q₁ and q₂ is F₁₂ and that between q₁ and q₃ is F₁₃, then (F₁₃)/(F₁₂)=

Asked in GUJCET 2018 · Coulomb's law and superposition

Answer: (1) 1/2

Step-by-step solution

Let the side of the square be a. With the charges on consecutive corners, q₁ and q₂ are joined by a side, and q₁ and q₃ by a diagonal.

r₁₂=a and r₁₃=a√2

The charges are equal, so F∝1/(r²):

(F₁₃)/(F₁₂)=(r₁₂²)/(r₁₃²)=(a²)/(2a²)=1/2

Why the other options are wrong

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