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Asked in GUJCET 2018 · Coulomb's law and superposition
Let the side of the square be a. With the charges on consecutive corners, q₁ and q₂ are joined by a side, and q₁ and q₃ by a diagonal.
r₁₂=a and r₁₃=a√2
The charges are equal, so F∝1/(r²):
(F₁₃)/(F₁₂)=(r₁₂²)/(r₁₃²)=(a²)/(2a²)=1/2
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