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Asked in GUJCET 2013 · Coulomb's law and superposition
Idea: a medium of dielectric constant K reduces the Coulomb force by the factor K.
In the medium: F=1/(4πε₀K)(q₁q₂)/(r²)
Medium withdrawn (vacuum): F₀=1/(4πε₀)(q₁q₂)/(r²)
(F₀)/F=K, so F₀=FK.
The force increases, because the medium's induced charges no longer screen the two charges from each other.
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