A point charge causes an electric flux of -1.0×10³ N m² C⁻¹ to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. If the radius of the Gaussian surface were three times as large, how much flux would pass through the surface?

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(2) -1.0×10³ N m² C⁻¹. Given: the flux through a sphere of radius 10.0 cm is -1.0×10³ N m² C⁻¹; the radius is made three times larger. Idea: Gauss's law, φ=(qᵢₙ)/(ε₀). The flux depends only on the charge enclosed, not on the size or shape of the surface. The charge inside is the same, so the flux is the same. Another view: the area grows as r² (by 9) while E falls as 1/(r²) (by 9), so E×4π r² does not change. φ=-1.0×10³ N m² C⁻¹

A point charge causes an electric flux of -1.0×10³ N m² C⁻¹ to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. If the radius of the Gaussian surface were three times as large, how much flux would pass through the surface?

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