Practice portal › Dual Nature of Matter and Radiation › Comparing de Broglie Wavelengths of Particles
Asked in GUJCET 2008 · Matter waves in other settings
Given: m_α = 4mₚ (two protons, two neutrons) and m_d = 2mₚ (one proton, one neutron); v_α = v, v_d = 2v.
Idea: λ = h/(mv), so compare the momenta.
p_α = 4mₚ× v = 4mₚ v and p_d = 2mₚ×2v = 4mₚ v.
The momenta are equal, so (λ_α)/(λ_d) = (p_d)/(p_α) = 1.
So the ratio of their de Broglie wavelengths is 1:1.
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