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The frequency of a photon having energy 100 eV is ______ Hz. (Take h = 6.62×10⁻³⁴ J s; 1 eV = 1.6×10⁻¹⁹ J)

Asked in GUJCET 2011 · Photon energy, momentum and mass

Answer: (2) 2.417×10¹⁶

Step-by-step solution

Given: E = 100 eV = 100×1.6×10⁻¹⁹ = 1.6×10⁻¹⁷ J.

Idea: E = hf, so f = E/h.

f = (1.6×10⁻¹⁷)/(6.62×10⁻³⁴) = 0.2417×10¹⁷ Hz

So f = 2.417×10¹⁶ Hz, in the extreme ultraviolet (wavelength about 12 nm).

Why the other options are wrong

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