Practice portal › Dual Nature of Matter and Radiation › Photon Energy, Number of Photons and Intensity
Asked in GUJCET 2011 · Photon energy, momentum and mass
Given: E = 100 eV = 100×1.6×10⁻¹⁹ = 1.6×10⁻¹⁷ J.
Idea: E = hf, so f = E/h.
f = (1.6×10⁻¹⁷)/(6.62×10⁻³⁴) = 0.2417×10¹⁷ Hz
So f = 2.417×10¹⁶ Hz, in the extreme ultraviolet (wavelength about 12 nm).
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer