Practice portal › Dual Nature of Matter and Radiation › Photon Energy, Number of Photons and Intensity
Asked in GUJCET 2023 · Counting photons
Given: P = 66 W, λ = 600 nm = 6×10⁻⁷ m, h = 6.6×10⁻³⁴ J s, c = 3×10⁸ m s⁻¹.
Idea: photons per second N = P/E, where each photon has E = (hc)/λ.
E = (6.6×10⁻³⁴×3×10⁸)/(6×10⁻⁷) = 3.3×10⁻¹⁹ J
N = (66)/(3.3×10⁻¹⁹) = 2×10²⁰ per second
So the bulb emits 2×10²⁰ photons per second.
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