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An electron and a proton are moving in the same direction with the same kinetic energy. The ratio of the de Broglie wavelength of the electron to that of the proton is ______.

Asked in GUJCET 2011 · Same or changed energy

Answer: (3) √(mₚ)/(mₑ)

Step-by-step solution

Given: Kₑ = Kₚ = K.

Idea: p = √2mK, so λ = h/(√2mK) ∝ 1/(√m) at fixed K.

(λₑ)/(λₚ) = √(2mₚK)/(2mₑK) = √(mₚ)/(mₑ)

With mₚ ≈ 1836 mₑ this is about 43: the electron's wavelength is much longer.

So the ratio is √(mₚ)/(mₑ).

Why the other options are wrong

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