Practice portal › Current Electricity › Combination of Resistors

n resistors, each of value R, are combined to get the maximum and the minimum effective resistance. The ratio of the maximum effective resistance to the minimum effective resistance is

Asked in GSEB Board March 2022 · Series and parallel combinations

Answer: (2) n²

Step-by-step solution

Idea: all n in series gives the largest resistance; all n in parallel gives the smallest.

Series: Rₘₐₓ=nR.

Parallel: 1/(Rₘᵢₙ)=n/R, so Rₘᵢₙ=R/n.

(Rₘₐₓ)/(Rₘᵢₙ)=(nR)/(R/n)=n².

Why the other options are wrong

More Combination of Resistors questionsAll Combination of Resistors questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer