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Asked in GSEB Board March 2022 · Series and parallel combinations
Idea: all n in series gives the largest resistance; all n in parallel gives the smallest.
Series: Rₘₐₓ=nR.
Parallel: 1/(Rₘᵢₙ)=n/R, so Rₘᵢₙ=R/n.
(Rₘₐₓ)/(Rₘᵢₙ)=(nR)/(R/n)=n².
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