Practice portal › Current Electricity › Combination of Resistors
Asked in GSEB Board July 2018 · Wires bent into shapes
Given: a uniform ring of total resistance R; ∠ POQ = π, so P and Q are the two ends of a diameter.
Idea: the two arcs between P and Q are in parallel, and the resistance of each arc is proportional to its length.
Each semicircle has resistance R/2.
R_PQ = ((R/2)(R/2))/(R/2 + R/2) = R/4.
So the equivalent resistance between P and Q is R/4.
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