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A light bulb is rated at 100 W for a 220 V supply. The resistance of the bulb is ______ ohm.

Asked in GSEB Board July 2021 · Rated bulbs and appliances

Answer: (1) 484

Step-by-step solution

Given: rated power P=100 W at V=220 V.

Idea: at its rated voltage the bulb dissipates its rated power, and P=(V²)/R.

R=(V²)/P=(220²)/(100).

R=(48400)/(100)=484 Ω.

Check: I=V/R=(220)/(484)=5/(11) A, and VI=220×5/(11)=100 W.

Why the other options are wrong

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