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The number density of free electrons in a copper conductor is estimated as 8.5×10²⁸ m⁻³. How long does an electron take to drift from one end of a wire 6 m long to its other end? The area of cross-section of the wire is 1.0×10⁻⁶ m² and it is carrying a current of 1.5 A.

Asked in GUJCET 2022 · Drift velocity, mobility and current density

Answer: (2) 5.4×10⁴ s

Step-by-step solution

Given: n = 8.5×10²⁸ m⁻³, ℓ = 6 m, A = 1.0×10⁻⁶ m², I = 1.5 A, e = 1.6×10⁻¹⁹ C.

Idea: I = neAv_d, so v_d = I/(neA), and the time to drift the length of the wire is t = ℓ/(v_d) = (neAℓ)/I.

neAℓ = 8.5×10²⁸×1.6×10⁻¹⁹×1.0×10⁻⁶×6 = 8.16×10⁴ C.

t = (8.16×10⁴)/(1.5) = 5.44×10⁴ s ≈ 5.4×10⁴ s, about 15 hours.

Why the other options are wrong

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