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The potential energy of the orbital electron in the ground state of hydrogen atom is -E. What is its kinetic energy?

Asked in GUJCET 2007 · Energy levels and ionisation

Answer: (3) E/2

Step-by-step solution

Given: potential energy U=-E in the ground state.

Idea: the Coulomb attraction supplies the centripetal force, (mv²)/r=(ke²)/(r²), so mv²=(ke²)/r.

Then K=1/2mv²=(ke²)/(2r) while U=-(ke²)/r, so K=-U/2.

K=-((-E))/2=E/2.

Why the other options are wrong

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