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What is the angular momentum of an electron of a Li-atom in the n=5 orbit?

Asked in GSEB Board March 2019 · Bohr's rules in other systems

Answer: (2) 5.27×10⁻³⁴ J s

Step-by-step solution

Idea: Bohr's quantisation condition fixes the angular momentum of the electron in the nth orbit as L=(nh)/(2π).

The nuclear charge does not appear in this condition, so the lithium nucleus changes nothing: only n matters.

L=(5×6.625×10⁻³⁴)/(2×3.14) J s.

L=5.27×10⁻³⁴ J s.

Why the other options are wrong

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