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The power in an A.C. circuit is given as P=VᵣₘₛIᵣₘₛ cos δ. The power factor at the resonance frequency of a series L–C–R circuit will be .........

Asked in RS Academy GUJCET booklet · Power factor

Answer: (2) 1

Step-by-step solution

The power factor is cos δ=R/Z.

At resonance X_L=X_C, so Z=√R²+(X_L-X_C)²=R.

Then cos δ=R/R=1 and δ=0: the current is in phase with the voltage.

The circuit behaves as a pure resistance and draws the most power, P=VᵣₘₛIᵣₘₛ.

So the power factor at resonance is 1.

Why the other options are wrong

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